3y^2-44y+156=0

Solution for 3y^2-44y+156=0 equation:

3y^2-44y+156=0

a = 3; b = -44; c = +156;
Δ = b2-4ac
Δ = -442-4·3·156
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-8}{2*3}=\frac{36}{6}
=6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+8}{2*3}=\frac{52}{6}
=8+2/3
$